Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 486: 39

Answer

The factor is $\frac{\sqrt 6}{\sqrt 6}$. After rationalizing: $\frac{2\sqrt 6}{3}$

Work Step by Step

The appropriate factor here is $\frac{\sqrt 6}{\sqrt 6}$. $\frac{4}{\sqrt {6}}=\frac{4}{\sqrt {6}}\times\frac{\sqrt 6}{\sqrt 6}=\frac{4\sqrt {6}}{6}=\frac{2\sqrt 6}{3}$
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