Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 486: 58

Answer

$\frac{6\sqrt{5}-5}{31}$

Work Step by Step

The given expression is $=\frac{\sqrt{5}}{6+\sqrt{5}}$ The conjugate of $6+\sqrt{5}$ is $6-\sqrt{5}$ $=\frac{\sqrt{5}}{6+\sqrt{5}} \cdot \frac{6-\sqrt{5}}{6-\sqrt{5}}$ Use sum and difference pattern. $=\frac{\sqrt{5}(6-\sqrt{5})}{6^2-(\sqrt{5})^2}$ Simplify. $=\frac{6\sqrt{5}-\sqrt{5}\cdot \sqrt{5}}{36-5}$ $=\frac{6\sqrt{5}-5}{31}$
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