Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 486: 59

Answer

$\sqrt{5}+\sqrt{2}$

Work Step by Step

The given expression is $=\frac{3}{\sqrt{5}-\sqrt{2}}$ The conjugate of $\sqrt{5}-\sqrt{2}$ is $\sqrt{5}+\sqrt{2}$ $=\frac{3}{\sqrt{5}-\sqrt{2}} \cdot \frac{\sqrt{5}+\sqrt{2}}{\sqrt{5}+\sqrt{2}}$ Use sum and difference pattern. $=\frac{3(\sqrt{5}+\sqrt{2})}{(\sqrt{5})^2-(\sqrt{2})^2}$ Simplify. $=\frac{3(\sqrt{5}+\sqrt{2})}{5-2}$ $=\frac{3(\sqrt{5}+\sqrt{2})}{3}$ $=\sqrt{5}+\sqrt{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.