Answer
$\frac{\sqrt[3] {x}}{\sqrt[3] x}$
Work Step by Step
Appropriate form of $1$ that can be used as a factor to eliminate the radical in the denominator is $\frac{\sqrt[3] {x}}{\sqrt[3] x}$.
The denominator then becomes
$\sqrt[3] {x^{2}}\cdot \sqrt[3] x=\sqrt[3] {x^{3}}=x$ and the radical is eliminated.
$\frac{2}{\sqrt[3]{x^2}}=\frac{2}{\sqrt[3]{x^2}}\times\frac{\sqrt[3]x}{\sqrt[3]x}=\frac{2\sqrt[3]x}{x}$
