Answer
$\frac{\sqrt{5}+8}{\sqrt {5}+8}$
Work Step by Step
The conjugate of $\sqrt {5}-8$ is $\sqrt {5}+8$.
Appropriate form of $1$ that can be used as a factor to eliminate the radical in the denominator is $\frac{\sqrt{5}+8}{\sqrt {5}+8}$.
The denominator then becomes
$(\sqrt {5}-8)\cdot (\sqrt {5}+8)=(\sqrt {5})^{2}-8^{2}=-59$ and the radical is eliminated.
