Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 486: 51

Answer

$\frac{\sqrt {15}}{5}d$

Work Step by Step

The given expression is $=\sqrt{\frac{3d^2}{5}}$ Use quotient property of square roots. $=\frac{\sqrt{3d^2}}{\sqrt{5}}$ Use product property of square roots. $=\frac{\sqrt{3}\cdot \sqrt{d^2}}{\sqrt{5}}$ Simplify. $=\frac{\sqrt{3}d}{\sqrt{5}}$ Multiply by $\frac{\sqrt {5}}{\sqrt {5}}$. $=\frac{\sqrt{3}d}{\sqrt{5}}\cdot \frac{\sqrt {5}}{\sqrt {5}}$ Use product property of square roots. $=\frac{\sqrt {3\cdot 5}d}{\sqrt {5\cdot 5}}$ Simplify. $=\frac{\sqrt {3\cdot 5}d}{\sqrt {5^2}}$ $=\frac{\sqrt {15}}{5}d$
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