Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 486: 52

Answer

$\frac{2\cdot \sqrt{6n}}{3n^2} $

Work Step by Step

The given expression is $=\frac{\sqrt{8}}{\sqrt{3n^3}}$ Multiply by $\frac{\sqrt{3n}}{\sqrt{3n}}$. $=\frac{\sqrt{8}}{\sqrt{3n^3}} \cdot \frac{\sqrt{3n}}{\sqrt{3n}} $ Use product property of square roots. $=\frac{\sqrt{8\cdot 3n}}{\sqrt{3n^3\cdot 3n}} $ Simplify. $=\frac{\sqrt{8\cdot 3n}}{\sqrt{3^2n^4}} $ Factor as square terms. $=\frac{\sqrt{4\cdot 2\cdot 3n}}{\sqrt{3^2n^4}} $ $=\frac{\sqrt{2^2\cdot 2\cdot 3n}}{\sqrt{3^2n^4}} $ Use product property of square roots. $=\frac{\sqrt{2^2}\cdot \sqrt{2\cdot 3n}}{\sqrt{3^2}\sqrt{n^4}} $ Simplify. $=\frac{2\cdot \sqrt{6n}}{3n^2} $
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