Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 485: 38

Answer

he second step is wrong and the correct answer is $\frac{4y\sqrt[3]{ 2}}{5}$.

Work Step by Step

The given expression is $=\sqrt[3]{\frac{128y^3}{125}}$ Use quotient property of cube roots. $=\frac{\sqrt[3]{128y^3}}{\sqrt[3]{125}}$ Factor as cube terms. $=\frac{\sqrt[3]{64y^3\cdot 2}}{\sqrt[3]{125}}$ Use $125=5^3$ and $64=4^3$. $=\frac{\sqrt[3]{4^3y^3\cdot 2}}{\sqrt[3]{5^3}}$ Simplify. $=\frac{4y\sqrt[3]{ 2}}{5}$ Hence, the second step is wrong and the correct answer is $\frac{4y\sqrt[3]{ 2}}{5}$.
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