Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 133: 7

$\text{x-intercept} =6$ $\text{y-intercept}=4$

$2x+3y=12$ To find the x-intercept, we substitute $0$ for $y$ and then solve for $x$ $2x+3(0)=12$ $\implies 2x=12$ $\implies x=\frac{12}{2}=6$ To find the y-intercept, we substitute $0$ for $x$ and then solve for $y$. $2(0)+3y=12$ $\implies 3y=12$ or $y=\frac{12}{3}=4$