Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 133: 16

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow -2x+6y=18$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow -2x+6(0)=18$ Simplify. $\Rightarrow -2x=18$ Divide each side by $-2$. $\Rightarrow \frac{-2x}{-2}=\frac{18}{-2}$ Simplify. $\Rightarrow x=-9$ The $x-$ intercept is $-9$, so plot the point $A=(-9,0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow -2(0)+6y=18$ Simplify. $\Rightarrow 0+6y=18$ $\Rightarrow 6y=18$ Divide each side by $6$. $\Rightarrow \frac{6y}{6}=\frac{18}{6}$ Simplify. $\Rightarrow y=3$ The $y-$ intercept is $3$, so plot the point $B=(0,3)$ Draw a line through the points $A$ and $B$.
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