Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 133: 17

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow -4x+3y=-30$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow -4x+3(0)=-30$ Simplify. $\Rightarrow -4x=-30$ Divide each side by $-4$. $\Rightarrow \frac{-4x}{-4}=\frac{-30}{-4}$ Simplify. $\Rightarrow x=\frac{15}{2}$ The $x-$ intercept is $\frac{15}{2}$, so plot the point $(\frac{15}{2},0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow -4(0)+3y=-30$ Simplify. $\Rightarrow 0+3y=-30$ $\Rightarrow 3y=-30$ Divide each side by $3$. $\Rightarrow \frac{3y}{3}=\frac{-30}{3}$ Simplify. $\Rightarrow y=-10$ The $y-$ intercept is $-10$, so plot the point $B=(0,-10)$ Draw a line through the points $A$ and $B$.
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