Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 133: 25

Answer

The last step is wrong. The correct answer is The $x-$ intercept is $8$, so the point is $A=(8,0)$. The $y-$ intercept is $2$, so the point is $B=(0,2)$.

Work Step by Step

The given linear equation is $\Rightarrow 3x+12y=24$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow 3x+12(0)=24$ Simplify. $\Rightarrow 3x=24$ Divide each side by $3$. $\Rightarrow \frac{3x}{3}=\frac{24}{3}$ Simplify. $\Rightarrow x=8$ The $x-$ intercept is $8$, so the point is $A=(8,0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow 3(0)+12y=24$ Simplify. $\Rightarrow 12y=24$ Divide each side by $12$. $\Rightarrow \frac{12y}{12}=\frac{24}{12}$ Simplify. $\Rightarrow y=2$ The $y-$ intercept is $2$, so the point is $B=(0,2)$ Hence, the last step is wrong.
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