Answer
The last step is wrong.
The $x-$ intercept is at $(5,0)$. and
the $y-$ intercept is at $(0,2)$.
Work Step by Step
The given linear equation is
$\Rightarrow 4x+10y=20$
$x$ intercept.
Substitute $0$ for $y$.
$\Rightarrow 4x+10(0)=20$
Simplify.
$\Rightarrow 4x=20$
Divide each side by $4$.
$\Rightarrow \frac{4x}{4}=\frac{20}{4}$
Simplify.
$\Rightarrow x=5$
The $x-$ intercept is $5$, so the point is $A=(5,0)$
$y$ intercept.
Substitute $0$ for $x$.
$\Rightarrow 4(0)+10y=20$
Simplify.
$\Rightarrow 10y=20$
Divide each side by $10$.
$\Rightarrow \frac{10y}{10}=\frac{20}{10}$
Simplify.
$\Rightarrow y=2$
The $y-$ intercept is $2$, so the point is $B=(0,2)$
Hence, the last step is wrong.