Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 133: 26

Answer

The last step is wrong. The $x-$ intercept is at $(5,0)$. and the $y-$ intercept is at $(0,2)$.

Work Step by Step

The given linear equation is $\Rightarrow 4x+10y=20$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow 4x+10(0)=20$ Simplify. $\Rightarrow 4x=20$ Divide each side by $4$. $\Rightarrow \frac{4x}{4}=\frac{20}{4}$ Simplify. $\Rightarrow x=5$ The $x-$ intercept is $5$, so the point is $A=(5,0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow 4(0)+10y=20$ Simplify. $\Rightarrow 10y=20$ Divide each side by $10$. $\Rightarrow \frac{10y}{10}=\frac{20}{10}$ Simplify. $\Rightarrow y=2$ The $y-$ intercept is $2$, so the point is $B=(0,2)$ Hence, the last step is wrong.
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