Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 133: 20

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow 3x-y=-5$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow 3x-0=-5$ Simplify. $\Rightarrow 3x=-5$ Divide each side by $3$. $\Rightarrow \frac{3x}{3}=-\frac{5}{3}$ Simplify. $\Rightarrow x=-\frac{5}{3}$ The $x-$ intercept is $-\frac{5}{3}$, so plot the point $A=(-\frac{5}{3},0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow 3(0)-y=-5$ Simplify. $\Rightarrow 0-y=-5$ $\Rightarrow -y=-5$ Multiply each side by $-1$. $\Rightarrow -1(-y)=-1(-5)$ Simplify. $\Rightarrow y=5$ The $y-$ intercept is $5$, so plot the point $B=(0,5)$ Draw a line through the points $A$ and $B$.
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