Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 133: 14

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow 4x+6y=12$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow 4x+6(0)=12$ Simplify. $\Rightarrow 4x=12$ Divide each side by $4$. $\Rightarrow \frac{4x}{4}=\frac{12}{4}$ Simplify. $\Rightarrow x=3$ The $x-$ intercept is $3$, so plot the point $A=(3,0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow 4(0)+6y=12$ Simplify. $\Rightarrow 0+6y=12$ $\Rightarrow 6y=12$ Divide each side by $6$. $\Rightarrow \frac{6y}{6}=\frac{12}{6}$ Simplify. $\Rightarrow y=3$ The $y-$ intercept is $2$, so plot the point $B=(0,2)$ Draw a line through the points $A$ and $B$.
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