Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 133: 15

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow -12x+3y=24$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow -12x+3(0)=24$ Simplify. $\Rightarrow -12x=24$ Divide each side by $-12$. $\Rightarrow \frac{-12x}{-12}=\frac{24}{-12}$ Simplify. $\Rightarrow x=-2$ The $x-$ intercept is $-2$, so plot the point $A=(-2,0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow -12(0)+3y=24$ Simplify. $\Rightarrow 0+3y=24$ $\Rightarrow 3y=24$ Divide each side by $3$. $\Rightarrow \frac{3y}{3}=\frac{24}{3}$ Simplify. $\Rightarrow y=8$ The $y-$ intercept is $8$, so plot the point $B=(0,8)$ Draw a line through the points $A$ and $B$.
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