Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 133: 21

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow -\frac{5}{2}x+y=10$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow -\frac{5}{2}x+0=10$ Simplify. $\Rightarrow -\frac{5}{2}x=10$ Multiply each side by $-\frac{2}{5}$. $\Rightarrow -\frac{2}{5}(-\frac{5}{2}x)=-\frac{2}{5}(10)$ Simplify. $\Rightarrow x=-4$ The $x-$ intercept is $-4$, so plot the point $A=(-4,0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow -\frac{5}{2}(0)+y=10$ Simplify. $\Rightarrow 0+y=10$ $\Rightarrow y=10$ The $y-$ intercept is $10$, so plot the point $B=(0,10)$ Draw a line through the points $A$ and $B$.
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