Chapter 9 Quadratic Relations and Conic Sections - 9.6 Translate and Classify Conic Sections - 9.6 Exercises - Skill Practice - Page 655: 7

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Given: $\frac{(x+2)^2}{16}+\frac{(y-2)^2}{36}=1$ Compare the given equation to the standard form of an equation of a circle. You can see that the graph is a circle with its center at $(h,k)=(-2,2)$ and $a=4,b=6$ Hence, the center of the circle is at $(-2,2)$. The vertices are at $(-2,8)$ and $(-2,-4)$ The co-vertices are at $(2,2)$ and $(-6,2)$