Answer
See below
Work Step by Step
Since the axis is horizontal $(h, k) =(-2, 3)$, then it should be: $$\frac{(x-(-2)^2}{25}+\frac{(y-3)^2}{9}=1\\\frac{(x+2)^2}{25}+\frac{(y-3)^2}{9}=1$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 9 Quadratic Relations and Conic Sections - 9.6 Translate and Classify Conic Sections - 9.6 Exercises - Skill Practice - Page 655: 21
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