Chapter 9 Quadratic Relations and Conic Sections - 9.6 Translate and Classify Conic Sections - 9.6 Exercises - Skill Practice - Page 655: 12

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Given: $\frac{(x-4)^2}{16}+\frac{(y-1)^2}{4}=1$ Compare the given equation to the standard form of an equation of an ellipse. You can see that the graph is an ellipse with center at $(h,k)=(4,1)$ and $a=4,b=2$. Hence, the center of the ellipse is at $(4,1)$ The co-vertices are at $(4,3)$ and $(4,-1)$