Answer
See below
Work Step by Step
The standard form for the parabola is $\frac{(y-k)^2}{a^2}+\frac{(x-h)^2}{b^2}=1$
We find $h=4\\k=7$
Distance from the center to a vertex: $a=3$
Distance from the center to a focus is: $c=5$
Find $c^2=a^2-b^2\\b^2=5^2-3^2\\b^2=16\\b=4$
We have an equation: $\frac{(x-4)^2}{9}-\frac{(y-7)^2}{16}=1$