Answer
See below
Work Step by Step
Given: $(x+4)^2=-8(y-2)$
Compare the given equation to the standard form of an equation of a parabola $(x-h)^2=4p(y-k)$. You can see that the graph is a circle with its center at $(h,k)=(-4,2)$
Plot some points: $(0,0);(-4,2);(-8,0)$
Draw a parabola.