Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.6 Translate and Classify Conic Sections - 9.6 Exercises - Skill Practice - Page 655: 10

Answer

See below

Work Step by Step

Given: $\frac{x^2}{25}+\frac{(y-2)^2}{4}=1$ Compare the given equation to the standard form of an equation of a parabola. You can see that the graph is a parabola with center at $(h,k)=(0,2)$ and $a=5,b=2$ Hence, the center is at $(0,2)$ The vertices are at $(5,2)$ and $(-5,2)$ The co-vertices are at $(0,4)$ and $(0,0)$ Draw a parabola.
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