Chapter 9 Quadratic Relations and Conic Sections - 9.6 Translate and Classify Conic Sections - 9.6 Exercises - Skill Practice - Page 655: 19

See below

The standard form for the parabola is $\frac{(y-k)^2}{a^2}+\frac{(x-h)^2}{b^2}=1$ We find $h=6\\k=-1$ Distance from the center to a vertex: $a=2$ Distance from the center to a focus is: $c=5$ Find $c^2=a^2-b^2\\b^2=5^2-2^2\\b^2=21\\b=\sqrt 21$ We have an equation: $\frac{(y+1)^2}{4}-\frac{(x-6)^2}{21}=1$