Algebra 1

by Hall, Prentice

Published by Prentice Hall

ISBN 10: 0133500403

ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 32

Answer

Answers may vary, and two possible solutions are provided. 34: $6n^2+34n+28 =(6n+28)(n+1)$ 59: $6n^2+59n+28 = (3n+28)(2n+1)$

Work Step by Step

$6n^2+xn+28$ $(6n+28)(n+1) = 6n^2+6n+28n+28 = 6n^2+34n+28$ $(3n+28)(2n+1) =6n^2+3n+56n+28 = 6n^2+59n+28$

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