Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 31

Answer

Answers may vary, but two possible solutions are below. 20: $9g^2 + 20g+4 = (9g+2)(g+2)$ 12: $9g^2 + 12g+4 = (3g+2)(3g+2)$

Work Step by Step

$9g^2+xg+4$ $(9g+2)(g+2) = 9g^2 +18g+2g+4 = 9g^2 + 20g+4$ $(3g+2)(3g+2) = 9g^2 +6g+6g+4 = 9g^2 + 12g+4$
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