Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 17

(3x-4)(x+9)

Given the polynomial $3x^{2}$ + 23x - 36 *** We break of the middle term into two factors that add to give +23 and multiply to give -108. The two numbers are +27 and -4. $3x^{2}$ + 27x - 4x - 36 We take the GCD of the first two and the GCD of the last two terms. 3x(x+9) -4(x+9) We take (x+9) and factor it out which gives us. (3x-4)(x+9)