Answer
2(x-4)(6x+1)
Work Step by Step
Given the polynomial
$12x^{2}$ - 46x - 8
We see that the three terms have a common factor of 2 so we factor out a 2.
2($6x^{2}$ - 23x - 4)
*** We break of the middle term into two factors that add to give -23 and multiply to give -24. The two numbers are -24 and +1.
2($6x^{2}$ - 24x + x - 4)
We take the GCD of the first two and the GCD of the last two terms.
2(6x(x-4)+1(x-4))
We take (x-4) and factor it out which gives us.
2(x-4)(6x+1)
