Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 16

(3t+5)(2t-1)

Given the polynomial $6t^{2}$ + 7t - 5 *** We break of the middle term into two factors that add to give +7 and multiply to give -30. The two numbers are +10 and -3. $6t^{2}$ + 10t -3t - 5 We take the GCD of the first two and the GCD of the last two terms. 2t(3t+5) -1(3t+5) We take (3t+5) and factor it out which gives us. (3t+5)(2t-1)