Answer
3(3r-5)(r+2)
Work Step by Step
Given the polynomial
$9r^{2}$ + 3r - 30
We see that the three terms have a common factor of 3 so we factor out a 3.
3($3r^{2}$ + r - 10)
*** We break of the middle term into two factors that add to give +1 and multiply to give -10. The two numbers are +6 and -5.
3($3r^{2}$ + 6r - 5r - 10)
We take the GCD of the first two and the GCD of the last two terms.
3(3r(r+2)-5(r+2))
We take (r+2) and factor it out which gives us.
3(3r-5)(r+2)
