Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 29

$(3v-8)(5v+3)$ $or$ $(3v+8)$$(5v-3)$

Given : $15v^{2}+[$ $]v-24$ Try $-31$ and $31$ Using $-31:$ $=15v^{2}+9v-40v-24$ $=$ $3v(5v+3)$ $-$ $8(5v+3)$ $=$ $(3v-8)$$(5v+3)$ Using $31:$ $=15v^{2}-9v+40v-24$ $=$ $3v(5v-3)$ $-$ $8(5v-3)$ $=$ $(3v+8)$$(5v-3)$