Answer
4(p+2)(3p-1)
Work Step by Step
Given the polynomial
$12p^{2}$ + 20p - 8
We see that the three terms have a common factor of 4. So we factor out a 4 which gives us.
4($3p^{2}$ + 5p - 2)
*** We break of the middle term into two factors that add to give +5 and multiply to give -6. The two numbers are +6 and -1.
4($3p^{2}$ + 6p - p - 2)
We take the GCD of the first two and the GCD of the last two terms.
4(3p(p+2)-1(p+2))
We take (p+2) and factor it out which gives us.
4(p+2)(3p-1)
