Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 19

(2d+5)(2d-7)

Given the polynomial $4d^{2}$ - 4d - 35 *** We break of the middle term into two factors that add to give -4 and multiply to give -140. The two numbers are +10 and -14. $4d^{2}$ + 10d - 14d - 35 We take the GCD of the first two and the GCD of the last two terms. 2d(2d+5) -7(2d+5) We take (2d+5) and factor it out which gives us. (2d+5)(2d-7)