Answer
$x=7$
$y=4$
Work Step by Step
$\frac{a^x}{a^y}=a^3$
$a^{x-y}=a^3$
Comparing the exponents of a on both sides:
$x-y=3$ (1)
$\frac{a^x}{a^3y}=a^{-5}$
$a^{x-3y}=a^{-5}$
Comparing the exponents of a on both sides:
$x-3y=-5$ (2)
From (1) and (2) we get:
$x-y=3$
$x-3y=-5$
Multiply both sides of the second equation with $-1$:
$x-y=3$
$-x+3y=5$
Using substitution:
$2y=8$
Solve for $y$:
$y=4$
Solve for $x$: $x-4=3$
$x=7$
