Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 67

Answer

$\frac{y^1{^0}}{2x^5}$

Work Step by Step

You have $\frac{4x^-{^2}y^4}{8x^3y^-{^6}}$. Simplify the expression: $\frac{x^-{^2}y^4}{2x^3y^-{^6}}$. -cancel out the common factor which is 4- $\frac{y^1{^0}}{2x^5}$. -subtract exponents with the same base- The simplified expression is $\frac{y^1{^0}}{2x^5}$
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