Answer
$c^{6}/a^{18}b^{6}$.
Work Step by Step
$=(a^{-1}b^{3}c/a^{2}b^{4})^{6}$
$=(b^{3}c/a^{1}a^{2}b^{4})^{6}$ (since $a^{-1}=1/a$)
$=(c/a^{(2+1)}b^{(4-3)})^{6}$ (since $a^{3}*a^{2}=a^{(3+2)}$)
$=(c/a^{(2+1)}b^{(4-3)})^{6}$
$=(c/a^{3}b)^{6}$
$=c^{6}/a^{(3*6)}b^{6}$ (since $(a^{b})^{c}=a^{bc}$)
$=c^{6}/a^{18}b^{6}$