Answer
$2/27$.
Work Step by Step
=$(1/4)^{-2}/(1/6)^{-3}$
=$(4^{-1})^{-2}/(6^{-1})^{-3}$
=$4^{2}/6^{3}$ (since $(a^{b})^{c}=a^{bc}$)
=$4*4/6*6*6$
=$2/27$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 73
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