Answer
$\frac{1}{9}$
Work Step by Step
You have $\frac{3x^3}{(3x)^3}$. Simplify the expression:
$\frac{3x^3}{3^3x^3}$ -apply rule (ab)${^n}$=$a^{n} $$b^{n}$-
$\frac{1}{3^2}$ -cancel out the common factor which is 3-
=$\frac{1}{9}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 62
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