Answer
$m^{6}p^{5}/n^{4}$.
Work Step by Step
$m^{4}n^{3}p^{-3}/m^{-2}n^{7}p^{-8}$
$m^{4}n^{3}*m^{2}p^{8}/p^{3}*n^{7}$ (since $a^{-1} = 1/a$)
$m^{6}p^{5}/n^{4}$. (since $a^{3}/a^{2}=a^{(3-2)}$ and $a^{3}*a^{2}=a^{(3+2)}$)
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 72
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
