Answer
$\frac{1}{16m^8}$
Work Step by Step
You have ($\frac{2m^4}{m^2}$$)^{-4}$.Simplify the expression:
$\frac{2m^4}{m^2}$=2$m^{2}$ -subtract the exponents because they have the same base-
(2$m^{2}$$)^{-4}$ -apply exponent rule $x^{-y}$=$\frac{1}{x^y}$-
$\frac{1}{(2m^2)^4}$ -apply rule (ab)${^n}$=$a^{n}
$$b^{n}$-
2$^4$=16 and (m$^2$)$^4$=m$^8$
The simplified expression is $\frac{1}{16m^8}.$
