Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 76

Answer

$(2^{8}*3^{6})$.

Work Step by Step

$=((-4)^{2}/(-3)^{-3})^{2}$ $=((-4)^{2*2}/(-3)^{-3*2})$ (since $(a^{b})^{c}=a^{bc}$) $=((-4)^{4}/(-3)^{-6})$ $=((-4)^{4}*(-3)^{6})$ (since $a^{-1}=1/a$) $=(4^{4}*3^{6})$ $=((2^{2})^{4}*3^{6})$ $=(2^{8}*3^{6})$
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