Answer
Radius of ion when it is in the second excited state is
r $=$ $1.058\times$$10^-$$^1$$^0m$
Work Step by Step
Radius of $n^t$$^h$ orbit is $=$ $r_n$$=$ $an^2/Z$
$a=constant=0.529\times10^-$$^1$$^0 m$
$Z=2 $$ , He$
$r^n=[0.529\times10^-$$^1$$^0 \times $ $(2)^2]/2$
$r^n=1.058\times10^-$$^1$$^0m$