Answer
470 Pa
Work Step by Step
Here we use Bernoulli's equation as follows.
$P+\frac{1}{2}\rho V^{2}+\rho gh= constant$
$P_{in}+\frac{1}{2}\rho V_{in}^{2}+0=P_{out}+\frac{1}{2}\rho V_{out}^{2}+0$
$P_{in}-P_{out}=\frac{1}{2}\rho (V_{out}^{2}-V_{in}^{2}) $ ; Let's plug known values into this equation.
$P_{in}-P_{out}=\frac{1}{2}(1.29\space kg/m^{3})(27\space m/s)^{2}\approx470\space Pa$
