Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 11 - Fluids - Problems - Page 311: 46

Answer

53506.2 kg

Work Step by Step

We can write, Buoyant force + Buoyant force on balloon = weight of the container on container $(F_{B})_{C}+(F_{B})_{B}=mg$ Since the container & the balloon are fully submerged in the water, by using the Archimedes principle, we can rewrite the above equation, $V_{C}\rho_{w}g+V_{B}\rho_{w}g=mg$ $m=\rho_{w}(V_{C}+V_{B})$ ; Let's plug known values into this equation. $m=(1025\space kg/m^{3})[(6.1)(2.4)(2.6)m^{3}+\frac{4}{3}\pi (1.5\space m)^{3}]=53506.2\space kg$ Mass of the container = 53506.2 kg
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