Answer
2.52 m/s
Work Step by Step
Here we use the equation 11.7 $mass\space flow\space rate=\rho AV$ to find the speed of the gasoline.
$mass\space flow\space rate=\rho AV$
$5.88\times10^{-2}kg/s=(753\space kg/m^{3})\pi (3.18\times10^{-3}m)^{2}V$
$V=2.52\space m/s$
Speed of the gasoline = 2.52 m/s
