Answer
(a) 0.18 m, (b) 0.14 m
Work Step by Step
Here we use equation 11.10 $Q=Av$
(a) $Q=Av$ ; Let's plug known values into this equation
$\frac{120\space m^{3}}{1200\space s}=L^{2}(3\space m/s)=> L=0.18\space m$
(b) $Q=Av$ ; Let's plug known values into this equation
$\frac{120\space m^{3}}{1200\space s}=L^{2}(5\space m/s)=> L=0.14\space m$
