Answer
$\Delta E_{th} = 153J$
Work Step by Step
$\Delta E_{th} = f_k \times d$
$\Delta E_{th} = (μ_kF_N) \times d$
$\Delta E_{th} = (μ_kmgcos\theta) \times d$
$\Delta E_{th} = (0.1\times 267\times 9.8 \times cos20^{\circ}) \times 6.1$
$\Delta E_{th} = 153J$