Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 206: 54a

Answer

$\Delta E_{th} = 153J$

Work Step by Step

$\Delta E_{th} = f_k \times d$ $\Delta E_{th} = (μ_kF_N) \times d$ $\Delta E_{th} = (μ_kmgcos\theta) \times d$ $\Delta E_{th} = (0.1\times 267\times 9.8 \times cos20^{\circ}) \times 6.1$ $\Delta E_{th} = 153J$
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