Answer
$U_{top}\approx 1.53\times 10^{6}J$
Work Step by Step
İf the potential energy is zero at the bottom of hill then the potential energy at top will be:
$U_{top}=U_{buttom}+mg\Delta h=0+520\times 9.8\times 300\approx 1.53\times 10^{6}J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 206: 51a
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