Answer
$$
W=5.6 \times 10^{2} \mathrm{J}
$$
Work Step by Step
The work done on the block by the worker is, using Eq. $7-7,$
$$
W=F d \cos \theta=[ 71 \mathrm{N} ]\ \ [ 9.2 \mathrm{m}]\ \mathrm{cos} 32^{\circ}=5.6 \times 10^{2} \mathrm{J}
$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 206: 42a
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