Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 206: 45a

Answer

30.1 J

Work Step by Step

Using the equation for work done by a constant force, we get: $W = Fdcos\theta$ $W = (7.68 N)(4.06 m) cos 15^{\circ}$ $W$ = 30.1 J
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